Exercise 4.1
Evaluate the determinants in Exercise 1 and 2.
So, |2A| = 4|A| (Hence Proved………)
5. Evaluate the determinants
⇒ |A| = 1(-9+12)-1(-18+15)-2(8-5)
⇒ |A| = 0
7. Find values of x, if
⇒ 2-20 = 2x2-24
⇒ -18 = 2x2-24
⇒ 2x2 = 24-18 = 6
⇒ x2 = 3
⇒ x = ±√3
⇒ 10-12 = 5x-6x
⇒ -2 = -x
⇒ x = 2
(A) 6 (B) ±6 (C) -6 (D) 0
⇒ x2 - 36 = 36 - 36
⇒ x2 = 36
⇒ x = ±6
Answer is ……… B.
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