Exercise 5.2
Differentiate the functions with respect to x in Exercises 1 to 8.
1. sin (x2+5)
Solun:- Let y = sin (x2+5)
Let t = x2+5
⇒ y = sin t
Differentiate w.r.t. x:-
⇒ t = x2+5
Differentiate w.r.t. x:-
2. cos (sin x)
Solun:- Let y = cos (sin x)
Let t = sin x
⇒ y = cos t
Differentiate w.r.t. x:-
⇒ t = sin x
Differentiate w.r.t. x:-
3. sin (ax+b)
Solun:- Let y = sin (ax+b)
Let t = ax+b
⇒ y = sin t
Differentiate w.r.t. x:-
⇒ t = ax+b
Differentiate w.r.t. x:-
4. sec (tan√x)
Solun:- Let y = sec (tan√x)
Let t = tan√x
⇒ y = sec t
Differentiate w.r.t. x:-
⇒ t = tan√x
Differentiate w.r.t. x:-
Let u = sin (ax+b) and v = cos (cx+d)
Differentiate w.r.t. x:-
6. cos x3 . sin2 (x5)
Solun:- Let y = cos x3 . sin2 (x5)
Let u = cos x3 and v = sin2 (x5)
Differentiate w.r.t. x:-
7. 2√cot(x2)
Solun:- Let y = 2√cot(x2)
Differentiate w.r.t. x:-
Applying Chain Rule:-
8. cos(√x)
Solun:- Let y = cos(√x)
Differentiate w.r.t. x:-
Applying Chain Rule:-
9. Prove that the function f given by f(x) = |x - 1|, x∈R is not differentiable at x = 1.
Solun:- Let f(x) = |x - 1|
We know for differentiability:-
R.H.D = L.H.D
R.H.D:-
At x>1
Put h = 0
= 1
L.H.D:-
At x<1
Put h = 0
= - 1
R.H.D ≠ L.H.D
Hence given function is not differentiable at x = 1.
10. Prove that the greater integer function defined by f(x) = [x], 0<x<3 is not differentiable at x = 1 and at x=2.
Solun:- Let f(x) = [x]
We know for differentiability:-
R.H.D = L.H.D
At x = 1
R.H.D:-
Put h = 0
= 0
L.H.D:-
Put h = 0
L.H.D is not defined.
Hence given function is not differentiable at x = 1.
At x = 2
R.H.D:-
Put h = 0
= 0
L.H.D:-
Put h = 0
L.H.D is not defined.
Hence given function is not differentiable at x = 2.
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